**Chapter
2 Linear Equations in One Variable**

**Exercise 2.1**

**Ex 2.1 Class 8 Maths **

**Question 1.
Solve the equation: x – 2 = 7.**

Solution:

Given: x – 2 = 7

**⇒**** x – 2 + 2 = 7 + 2 (adding 2 on both
sides)
**

**⇒**

**x = 9 (Required solution)**

**Ex 2.1 Class 8 Maths **

**Question 2.
Solve the equation: y + 3 = 10.**

Given: y + 3 = 10

Given: y + 3 = 10

**⇒**

**y + 3 – 3 = 10 – 3 (subtracting 3 from each side)**

**⇒**

**y = 7 (Required solution)**

**Ex 2.1 Class 8 Maths **

**Question 3.
Solve the equation: 6 = z + 2**

Solution:

We have 6 = z + 2

Solution:

We have 6 = z + 2

**⇒**

**6 – 2 = z + 2 – 2 (subtracting 2 from each side)**

**⇒**

**4 = z**

Thus, z = 4 is the required solution.

Thus, z = 4 is the required solution.

**Ex 2.1 Class 8 Maths **

**Question 4.
Solve the equations: **

**+ x =**

Solution:

Solution:

**Ex 2.1 Class 8 Maths **

**Question 5.
Solve the equation 6x = 12.**

Solution:

We have 6x = 12

Solution:

We have 6x = 12

**⇒**

**6x ÷ 6 = 12 ÷ 6 (dividing each side by 6)**

**⇒**

**x = 2**

Thus, x = 2 is the required solution.

Thus, x = 2 is the required solution.

**Ex 2.1 Class 8 Maths **

**Question 6.
Solve the equation **

**= 10.**

Solution:

Given
= 10

Solution:

Given

**⇒**

× 5 = 10 × 5 (multiplying both sides by 5)

**⇒**

**t = 50**

Thus, t = 50 is the required solution.

Thus, t = 50 is the required solution.

**Ex 2.1 Class 8 Maths **

**Question 7.
Solve the equation **

**= 18.**

Solution:

We have

**⇒****
**

**⇒**

**2x = 54**

**⇒**

**2x ÷ 2 = 54 ÷ 2 (dividing both sides by 2)**

**⇒**

**x = 27**

Thus, x = 27 is the required solution.

Thus, x = 27 is the required solution.

**Ex 2.1 Class 8 Maths **

**Question 8.
Solve the equation 1.6 = **

Solution:

Given: 1.6 =

**⇒**** 1.6 × 1.5 =
**

**⇒**

**2.40 = y**

Thus, y = 2.40 is the required solution.

Thus, y = 2.40 is the required solution.

**Ex 2.1 Class 8 Maths **

**Question 9.
Solve the equation 7x – 9 = 16.**

Solution:

We have 7x – 9 = 16

**⇒**** 7x – 9 + 9 = 16 + 9 (adding 9 to
both sides)
**

**⇒**

**7x = 25**

**⇒**

**7x ÷ 7 = 25 ÷ 7 (dividing both sides by 7)**

**⇒**

**x =**

Thus, x =
is the required solution.

Thus, x =

**Ex 2.1 Class 8 Maths **

**Question 10.
Solve the equation 14y – 8 = 13.**

Solution:

We have 14y – 8 = 13

**⇒**** 14y – 8 + 8 = 13 + 8 (adding 8 to
both sides)
**

**⇒**

**14y = 21**

**⇒**

**14y ÷ 14 = 21 ÷ 14 (dividing both sides by 14)**

**⇒**

**y =**

**⇒**

**y =**

Thus, y =
is the required solution.

Thus, y =

**Ex 2.1 Class 8
Maths Question 11.
Solve the equation 17 + 6p = 9.**

Solution:

We have, 17 + 6p = 9

**⇒**** 17 – 17 + 6p = 9 – 17 (subtracting
17 from both sides)
**

**⇒**

**6p = -8**

**⇒**

**6p ÷ 6 = -8 ÷ 6 (dividing both sides by 6)**

**⇒**

**p =**

**⇒**

**p =**

Thus, p =
is the required solution.

Thus, p =

**Ex 2.1 Class 8
Maths Question 12.
Solve the equation **

**+ 1 =**

0comments