**Chapter
16 Playing with Numbers**

**Exercise 16.1**

**Find the values of the letters in each of the following and
give reasons for the steps involved.**

Ex 16.1 Class 8 Maths Question
1.

Solution:

**Ex 16.1 Class 8 Maths Question
2.**

Solution:

**Ex 16.1 Class 8
Maths Question 3.
**

Solution:

Solution:

**Ex 16.1 Class 8
Maths Question 4.**

Solution:

**Ex 16.1 Class 8
Maths Question 5.**

Solution:

3 × B = B

**⇒**** B = D
3 × A = CA
**

**⇒**

**3 × 5 = 15**

Thus A = 5 and C = 1

Hence A = 5, B = 0 and C = 1

Thus A = 5 and C = 1

Hence A = 5, B = 0 and C = 1

**Ex 16.1 Class 8
Maths Question 6.**

Solution:

5 × B = B

**⇒**** B = 0 or 5
5 × A = CA
5 × 5 = 25
Only possible when B = 0
Thus A = 5 and C = 2
Hence A = 5, B = 0 and C = 2**

**Ex 16.1 Class 8
Maths Question 7.**

Solution:

B × 6 = B

6 × 4 = 24 → B = 4 and 2 is carried to

6 × A = BB

**⇒**** 6 × 7 = 42 + 2 (carried on) = 44
Thus B = 7
Hence A = 7 and B = 4**

**Ex 16.1 Class 8
Maths Question 8.**

Solution:

1 + B = 0

1 + 9 = 10 → unit digit is 0 and 1 is carried to A

+ 1 +1 (carried on) = B = 9

A + 2 = 9 **⇒**** A = 9 – 2 =
7
Hence A = 7 and B = 9**

**Ex 16.1 Class 8
Maths Question 9.**

Solution:

B + 1 = 8 **⇒**** B = 8 – 1 =
7
A + B = a number with unit digit 1
A + B = 11
**

**⇒**

**A + 7 = 11**

**⇒**

**A = 11 – 7 = 4 (1 Carried to)**

Now 1 carried on + 2 + A = B

3 + A = 7

Now 1 carried on + 2 + A = B

3 + A = 7

**⇒**

**A = 7 – 3 = 4**

Hence A = 4, B = 7

Hence A = 4, B = 7

**Ex 16.1 Class 8
Maths Question 10.**

Solution:

9 = A + B

9 = 1 + 8 or 2 + 7 or 3 + 6 or 4 + 5 or 8 + 1 or 7 + 2 or 6 + 3 or 5 + 4 or 0 +
9 or 9 + 0

Now 0 is required at unit place

2 + A = 10

**⇒**** A = 10 – 2 = 8
B = 9 – 8 = 1
1 + 6 + 1 (carried on) = A = 8
Hence A = 8 and B = 1**

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